Name : ____________________    Date   : _____________

                                                      Score : _____________

Write down your correct answer and show your workings:

  1)  There are altogether 114 beans in bags A, B and C. 
       There are 8 more beans in bag A than B. 
       The number of beans in bag C is twice the total number of beans in bags A and B. 
       How many more beans are there in bag C than B?
 
 
 
 
 
 
 
 
 
 
 
 
 
 

  2)  Salwa and Deva have $187 altogether. 
       Deva and Jason have $173 altogether. 
       Salwa and Jason have $152 altogether. 
       How much money does Salwa have? 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

  3)  3 handbags and 3 belts cost $1422
       The cost of 1 belt is half the cost of 1 handbag.
       Find the cost of 1 handbag.
 
 
 
 
 
 
 
 
 
 
 
 
 

  4)  Karen has $40 more than Ali.
       After Karen bought a dress for $180 and Ali bought a tennis racket for $200, 
       Karen had twice the amount of money Ali had.
       How much money did Karen have at first?
 
 
 
 
 
 
 
 
 
 
 
 
 
 

  5)  Gerrard has 208 stickers and Irene has 78 stickers. 
       How many stickers must Gerrard give to Irene so that they have the same number of stickers?
 
 
 
 
 
 
 
 
 
 
 
 
 
 

Answers:

  1) A  1u + 8 
      B   1u
      C   1u   1u  1u   1u  + 16 
      6u + 24 = 114
      6u = 114 - 24 = 90
      1u = 90 / 6 = 15

      C - B (How many more beans are there in bag C than B?)
      4u - 1u + 16 
      3u x 15 +16
       45 + 16 = 61

Notes:
(8 more beans in bag A than B so A = 1u + 8)
bag C is twice the total number of beans in bags A and B
(C = A and B x 2 so = 2u x 2 = 4u and 8 x 2 = 16 u)

  2)  (S)alwa and (D)eva
       S + D --> 187 (1)
       D + J --> 173 (2)
       S + J --> 152 (3)

       2S + 2D + 2J --> 187+173+152 = 512 (4) 
       S + D + J --> 512 / 2 = 256 (5) 

       S --> 256 - 173 = 83 (4) - (2) 

Notes:
Finally, you minus D + J to get S.

   3) 1422 / 9 = 158 
       158 x 2 = 316
       The cost of 1 handbag is $316

Notes:
The cost of 1 belt is half the cost of 1 handbag.  So 3 hangbag x 2 = 6 handbag. 
Total = 6 (handbag) + 3 (belt) = 9.
Finally, you need to multiply by 2 as original is still 1 hangbag.

    4) 

        1u = 60
        60 + 60 + 140 + 40 = 300
        Karen have 300 at first.

Notes:
$180 - $40 = $140 (The amount bought for dress - difference)
As such:
1u = $200 - $140 = $60
Karen at first = $60 x 2 + $180 = $300

    5) 208 - 78
        130 / 2 = 65
        Gerrard must give Irene 65 stickers.

Notes:
(1) Deduct the differences.
     Then divide by 2 to share equally.
     208 - 65 = 143
     78 + 65 = 143

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