I've got several files in different directories like this:

aa/t1
aa/bb/t2
aa/t2
aa/bb/cc/t1
aa/t3

and would like to get this sorting:

aa/t1
aa/bb/cc/t1
aa/t2
aa/bb/t2
aa/t3

Which means, sorting all files considering the last number in the name of the file.

Code:

find ... |
  perl -le'
    print sort {
        ($aa) = $a =~ /(\d+)$/;
        ($bb) = $b =~ /(\d+)$/;
        $aa <=> $bb
      } <>
      '
 

Please provide a small script for the following senario:

step1: need to find some files in a directory for ex having 020909
step2: sort them and redirecting to new file
(ex:sort abc > abc.sort)

I am trying this but giveing flag error 
ls -l *.020909* |grep -v .sort| while read file
do
sort "$file" > "$file".sort
done

In your original script "ls -l" (ell) should have been "ls -1" (one) to just get the filename.

Here's a version with some minor tweaks. It starts with ls hyphen one.

ls -1 *\.020909* 2>/dev/null | grep -v "\.sort$" | while read file1
do
file2="${file1}.sort"
echo "Sorting ${file1} into ${file2}"
sort < "${file1}" > "${file2}"
done

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